Test AEE CEM Simulator Online, CEM Braindumps
Test AEE CEM Simulator Online, CEM Braindumps
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Tags: Test CEM Simulator Online, CEM Braindumps, CEM Online Version, CEM Valid Test Cost, CEM Guide
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AEE Certified Energy Manager (CEM) Sample Questions (Q71-Q76):
NEW QUESTION # 71
An energy-saving project costs $540,000. The project will have maintenance costs of $25,000 per year. The energy savings from the project are $160,000 per year. What is the simple payback of the project?
- A. 3.0 years
- B. 4.0 years
- C. 2.0 years
- D. 5.0 years
Answer: B
Explanation:
To determine the simple payback period for the energy-saving project, we need to apply the standard formula used in energy management as per the Association of Energy Engineers (AEE) Certified Energy Manager (CEM) guidelines. The simple payback period is a widely used metric in energy efficiency projects to evaluate how long it takes for the initial investment to be recovered through net savings. Let's break this down step-by-step using the provided data and CEM-aligned methodology.
Step 1: Understand the Simple Payback Formula
* Formula: Simple Payback Period (years)=Initial Investment CostNet Annual Savingstext{Simple Payback Period (years)} = frac{text{Initial Investment Cost}}{text{Net Annual Savings}} Simple Payback Period (years)=Net Annual SavingsInitial Investment Cost
* Definition: The simple payback period represents the time (in years) required for the cumulative savings to equal the initial investment, without considering the time value of money (e.g., discount rates or inflation).
* CEM Reference: AEE CEM training materials emphasize this formula in the "Energy Economics" section, where simple payback is a fundamental tool for assessing project feasibility.
Step 2: Identify Given Data
* Initial Investment Cost: $540,000 (one-time cost of the project).
* Annual Energy Savings: $160,000 per year (benefit from the project).
* Annual Maintenance Costs: $25,000 per year (additional cost incurred due to the project).
* Net Annual Savings: This must account for both the savings and the costs incurred annually.
Step 3: Calculate Net Annual Savings
* Definition: Net annual savings is the difference between the annual energy savings and any additional annual costs (e.g., maintenance).
* Verification: The problem specifies maintenance costs as an ongoing expense tied to the project, which reduces the effective savings. CEM guidelines require including such costs in payback calculations unless explicitly stated otherwise.
Step 4: Compute the Simple Payback Period
* Apply the Formula: Simple Payback Period=Initial Investment CostNet Annual Savingstext{Simple Payback Period} = frac{text{Initial Investment Cost}}{text{Net Annual Savings}} Simple Payback Period=Net Annual SavingsInitial Investment Cost Simple Payback Period=540,
000135,000=4.0 yearstext{Simple Payback Period} = frac{540,000}{135,000} = 4.0 , text{years} Simple Payback Period=135,000540,000=4.0years
* Result: The payback period is exactly 4.0 years, meaning it takes 4 years for the net savings to recover the initial investment.
Step 5: Validate Against Options
* Options:A. 2.0 yearsB. 3.0 yearsC. 4.0 yearsD. 5.0 years
* Check:
* If we ignored maintenance costs (incorrectly), payback would be 540,000160,000=3.375 frac
{540,000}{160,000} = 3.375 160,000540,000=3.375 years, which rounds to 3.4-not an exact match for any option.
* With maintenance costs included, 540,000135,000=4.0 frac{540,000}{135,000} = 4.0
135,000540,000=4.0, which matches option C precisely.
* Conclusion: Option C (4.0 years) is correct based on the net savings approach.
NEW QUESTION # 72
Which type of lighting control technique operates in "manual on" and "auto-off mode, and can be used in situations where there is brief occupancy that do not need lights on?
- A. Photocell control
- B. Vacancy sensor
- C. PIR/Microphonics dual technology
- D. Microphonics technology
- E. Occupancy sensor
Answer: B
NEW QUESTION # 73
Using an interest rate of 15%, an energy project has a net-present value (NPV) of $3,500. Which statement is true about the project's internal rate of return (IRR)?
- A. IRR < 15%
- B. IRR = 15%
- C. IRR < 0%
- D. IRR > 15%
Answer: D
NEW QUESTION # 74
An energy-saving project costs $540,000. The project will have maintenance costs of $25,000 per year. The energy savings from the project are $160,000 per year. The project has a life of 10 years with no salvage value. The minimum attractive rate of return (MARR) is 10%. Using end-of-year cash flows, calculate the net- present value (NPV) of the project.
- A. $154,657
- B. $311,556
- C. $289,575
- D. $456,254
Answer: C
Explanation:
A screenshot of a math formula AI-generated content may be incorrect.
NEW QUESTION # 75
Which type of single-phase alternating-current motor has the highest efficiency?
- A. Permanent split-capacitor motor
- B. Electronic-commutated motor
- C. Shaded-pole motor
Answer: B
NEW QUESTION # 76
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